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X^2+2X=5.25
We move all terms to the left:
X^2+2X-(5.25)=0
We add all the numbers together, and all the variables
X^2+2X-5.25=0
a = 1; b = 2; c = -5.25;
Δ = b2-4ac
Δ = 22-4·1·(-5.25)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-5}{2*1}=\frac{-7}{2} =-3+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+5}{2*1}=\frac{3}{2} =1+1/2 $
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